Optimal. Leaf size=376 \[ \frac{\left (5 a^2 B+14 a A b-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{\left (30 a^2 A b+5 a^3 B-40 a b^2 B-16 A b^3\right ) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{8 \sqrt{b} d}-\frac{(-b+i a)^{5/2} (A+i B) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{(3 a B+2 A b) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{(b+i a)^{5/2} (A-i B) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)} \]
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Rubi [A] time = 2.96984, antiderivative size = 376, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 11, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.314, Rules used = {4241, 3607, 3647, 3655, 6725, 63, 217, 206, 93, 205, 208} \[ \frac{\left (5 a^2 B+14 a A b-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{\left (30 a^2 A b+5 a^3 B-40 a b^2 B-16 A b^3\right ) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{8 \sqrt{b} d}-\frac{(-b+i a)^{5/2} (A+i B) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{(3 a B+2 A b) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{(b+i a)^{5/2} (A-i B) \sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Rule 4241
Rule 3607
Rule 3647
Rule 3655
Rule 6725
Rule 63
Rule 217
Rule 206
Rule 93
Rule 205
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+b \tan (c+d x))^{5/2} (A+B \tan (c+d x))}{\sqrt{\cot (c+d x)}} \, dx &=\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \int \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^{5/2} (A+B \tan (c+d x)) \, dx\\ &=\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{1}{3} \left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \int \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)} \left (\frac{3}{2} a (2 a A-b B)+3 \left (2 a A b+a^2 B-b^2 B\right ) \tan (c+d x)+\frac{3}{2} b (2 A b+3 a B) \tan ^2(c+d x)\right ) \, dx\\ &=\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \int \frac{\sqrt{a+b \tan (c+d x)} \left (-\frac{3}{4} a b (2 A b+3 a B)+6 b \left (a^2 A-A b^2-2 a b B\right ) \tan (c+d x)+\frac{3}{4} b \left (14 a A b+5 a^2 B-8 b^2 B\right ) \tan ^2(c+d x)\right )}{\sqrt{\tan (c+d x)}} \, dx}{6 b}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \int \frac{-\frac{3}{8} a b \left (18 a A b+11 a^2 B-8 b^2 B\right )+6 b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) \tan (c+d x)+\frac{3}{8} b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tan ^2(c+d x)}{\sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}} \, dx}{6 b}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{-\frac{3}{8} a b \left (18 a A b+11 a^2 B-8 b^2 B\right )+6 b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x+\frac{3}{8} b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) x^2}{\sqrt{x} \sqrt{a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{6 b d}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \left (\frac{3 b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right )}{8 \sqrt{x} \sqrt{a+b x}}-\frac{6 \left (b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x\right )}{\sqrt{x} \sqrt{a+b x} \left (1+x^2\right )}\right ) \, dx,x,\tan (c+d x)\right )}{6 b d}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}-\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x}{\sqrt{x} \sqrt{a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{b d}+\frac{\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{16 d}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}-\frac{\left (\sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \left (\frac{i b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )+b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right )}{2 (i-x) \sqrt{x} \sqrt{a+b x}}+\frac{i b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right )}{2 \sqrt{x} (i+x) \sqrt{a+b x}}\right ) \, dx,x,\tan (c+d x)\right )}{b d}+\frac{\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^2}} \, dx,x,\sqrt{\tan (c+d x)}\right )}{8 d}\\ &=\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left ((a-i b)^3 (A-i B) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} (i+x) \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}-\frac{\left ((a+i b)^3 (A+i B) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{(i-x) \sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}+\frac{\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{8 d}\\ &=\frac{\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}}{8 \sqrt{b} d}+\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}+\frac{\left ((a-i b)^3 (A-i B) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{i-(-a+i b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}-\frac{\left ((a+i b)^3 (A+i B) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{i-(a+i b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}\\ &=-\frac{(i a-b)^{5/2} (A+i B) \tan ^{-1}\left (\frac{\sqrt{i a-b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}}{d}+\frac{\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}}{8 \sqrt{b} d}+\frac{(i a+b)^{5/2} (A-i B) \tanh ^{-1}\left (\frac{\sqrt{i a+b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right ) \sqrt{\cot (c+d x)} \sqrt{\tan (c+d x)}}{d}+\frac{\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt{a+b \tan (c+d x)}}{8 d \sqrt{\cot (c+d x)}}+\frac{b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac{3}{2}}(c+d x)}+\frac{(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt{\cot (c+d x)}}\\ \end{align*}
Mathematica [A] time = 4.95521, size = 365, normalized size = 0.97 \[ \frac{\sqrt{\tan (c+d x)} \sqrt{\cot (c+d x)} \left (3 \left (5 a^2 B+14 a A b-8 b^2 B\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}+\frac{3 \sqrt{a} \left (30 a^2 A b+5 a^3 B-40 a b^2 B-16 A b^3\right ) \sqrt{\frac{b \tan (c+d x)}{a}+1} \sinh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{\sqrt{b} \sqrt{a+b \tan (c+d x)}}+6 (3 a B+2 A b) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^{3/2}-24 \sqrt [4]{-1} (-a-i b)^{5/2} (A+i B) \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{-a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )-24 \sqrt [4]{-1} (a-i b)^{5/2} (A-i B) \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )+8 b B \tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))^{3/2}\right )}{24 d} \]
Antiderivative was successfully verified.
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Maple [C] time = 2.418, size = 36039, normalized size = 95.9 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \tan \left (d x + c\right ) + A\right )}{\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}{\sqrt{\cot \left (d x + c\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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